D and E is sort of a trick it appears, since they are both technicalyl in the same parallel circuit as A. Where B and C are a series circuit within the parallel. I can't remember which does what though; one decreases voltage while the other decreases amperage or something? Edit: I think Agares has it right, at A, B, D, E, C, if in fact the negative lead on the left reaches C last due to subsequent parallel circuits terminating last on the positive side, and the series circuitry causing the most resistance to C altogether.